[sanamine]

ariepfadli said:

did u mean ABS (alkyl benzene sulphonate)? each molecule LABSA (mw=329) need 3 molecule of lye (NaOH mw=40) just calculate it, it seem need 1540 gram NaOH, it should be resulted white with slightly yellowish paste

Exactely i meant alky benzene sulphonate, and as you said it resulted with a slightly yellowish paste. 

[sanamine]

Abdullah said:

It is about 75% active

75.428571428571%

Thank you very much Abdullah. So, if i didn’t a mistake i suppose full resultants are : 
Active content is (75%)
Sodium sulfate approximately (2%)
Water is (23%)