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Assay/ concentration
Are assay and concentration same in effect while formulating?
While formulating detergents or any other product, if commercially available raw material is at a lower concentration than needed, can we use it in larger quantity.
For eg., SLES is needed at 69% assay . I am getting it in 28% concentration. Can I use the 28% SLES in increased ratio?
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6 Replies
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If you need 69% SLES in your formula and the raw material is supplied as 28% you won’t be able to do it. You would have to evaporate off some of the water to increase the concentration of SLES.
For every 100 grams of a 28% solution you put in, you are only putting in 28 grams of SLES.
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The lower the assay the more you need to supply the ingredient you are after.
The maths is simple: What you want, divided by what you have, multiplied by 100.
So, 69 %/28% x 100 = 246.4% which clearly will not work.
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Perry said:If you need 69% SLES in your formula and the raw material is supplied as 28% you won’t be able to do it. You would have to evaporate off some of the water to increase the concentration of SLES.
For every 100 grams of a 28% solution you put in, you are only putting in 28 grams of SLES.
Thanks Perry.
I understand that evaporating is a sure shot solution.
Can adding additional amount help too?
My formula states 10 % of 69% SLES (it is a water based formula)
So, 10*69/28 =24.6 % _ That is, 28% SLES in the amount 24.6 %
Here, I am adding additional water with the 28% SLES so I shall deduct water in the formula proportionately.
Can this be done?
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If you are adding 10% of a 69% SLES solution, that means you are adding 6.9 grams in 100 grams. So, to get 6.9 you would need 24.6% of the 28% solution. Then subtract the excess volume from the water.
Yes, that would work.
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Thanks again Perry .
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Herbnerd said:The lower the assay the more you need to supply the ingredient you are after.
The maths is simple: What you want, divided by what you have, multiplied by 100.
So, 69 %/28% x 100 = 246.4% which clearly will not work.
Thanks Herbnerd.
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